4.9x^2+9x+2.25=0

Solution for 4.9x^2+9x+2.25=0 equation:

4.9x^2+9x+2.25=0

a = 4.9; b = 9; c = +2.25;
Δ = b2-4ac
Δ = 92-4·4.9·2.25
Δ = 36.9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{36.9}}{2*4.9}=\frac{-9-\sqrt{36.9}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{36.9}}{2*4.9}=\frac{-9+\sqrt{36.9}}{9.8}
$